4^(x-1)*(.25)^(3-2x)=(1/8)^x

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Solution for 4^(x-1)*(.25)^(3-2x)=(1/8)^x equation: 



4^(x-1)(.25)^(3-2x)=(1/8)^x

We move all terms to the left:

4^(x-1)(.25)^(3-2x)-((1/8)^x)=0



Domain of the equation: 8)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4^(x-1)(0.25)^(-2x+3)-((+1/8)^x)=0

We multiply parentheses ..

4^(+0.25x-0.25)^(-2x+3)-((+1/8)^x)=0

We multiply all the terms by the denominator


(4^(+0.25x-0.25)^(-2x+3))*8)^x)-((+1=0

We add all the numbers together, and all the variables

(4^(0.25x-0.25)^(-2x+3))*8)^x)-((+1=0

We move all terms containing x to the left, all other terms to the right

(4^(0.25x-0.25)^(-2x+3))*8)^x)-((=-1

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